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Old 04-22-2008, 06:57 PM   #1
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Default 250 hp motor

Where can I find what wire size is recommended for a 250hp 480v motor?
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Old 04-22-2008, 07:06 PM   #2
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By taking the FLA from the spec plate and matching the wire to the amperage.
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Old 04-22-2008, 07:14 PM   #3
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HP x 746
1.73 x E x Eff x PF


This will put you in the ballpark for amps.
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Old 04-22-2008, 07:44 PM   #4
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Originally Posted by Controls Guy View Post
Where can I find what wire size is recommended for a 250hp 480v motor?
The NEC requires that you size the branch circuit conductors for motors using the ampacity tables in the back of Article 430.

Take a look at 430.22(A) for a single motor.

You can't use the motor nameplate FLA's to size the branch circuit conductors. You are only permitted to use the motor nameplate FLA's for sizing the motor overload protection.(See 430.6(A)(2))

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Old 04-22-2008, 07:52 PM   #5
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If you take a look at Table 430.250 you will see that a 250 HP 3 phase 460 volt motor has an ampacity of 302 amps.

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Old 04-22-2008, 08:08 PM   #6
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Originally Posted by raider1 View Post
The NEC requires that you size the branch circuit conductors for motors using the ampacity tables in the back of Article 430.

Take a look at 430.22(A) for a single motor.

You can't use the motor nameplate FLA's to size the branch circuit conductors. You are only permitted to use the motor nameplate FLA's for sizing the motor overload protection.(See 430.6(A)(2))

Chris

Take a look at the book and read that section, keeping in mind it's a 250 hp motor, more than likely a pump motor.
You maybe surprised.
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Old 04-23-2008, 12:20 AM   #7
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i thought it was HP (250) times 746 (watts per HP) 250 X 746 = 186500 then you divide that by the voltage (480) 186500 / 480 = 388.54 then you take 125% if it is considered a continuous load so 388.54 X 1.25 = 485.675 so rounded it would be 486 amps.
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Old 04-23-2008, 06:30 AM   #8
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Quote:
Originally Posted by pudge565 View Post
i thought it was HP (250) times 746 (watts per HP) 250 X 746 = 186500 then you divide that by the voltage (480) 186500 / 480 = 388.54 then you take 125% if it is considered a continuous load so 388.54 X 1.25 = 485.675 so rounded it would be 486 amps.
You are leaving out efficiency,power factor, and the fact its three phase on the divisor.

259x746
________
1.73(3phase factor)x 480xefficiency x power factor

then x 125%
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Old 04-23-2008, 06:40 AM   #9
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Not having had to design any circuits for large HP motors, how does one determine values for "efficiency" and power factor?

Seems to me, the horsepower rating is meaningless without a value for amperage. Also, I wonder why the FLA can't be used since it reflects the current limiting effects of impedance.

My vote is that electricians work with what engineers have designed. Let's stop forcing the trade to serve as low paid engineers, huh?
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Old 04-23-2008, 06:46 AM   #10
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Originally Posted by waco View Post
Not having had to design any circuits for large HP motors, how does one determine values for "efficiency" and power factor?

Seems to me, the horsepower rating is meaningless without a value for amperage. Also, I wonder why the FLA can't be used since it reflects the current limiting effects of impedance.

My vote is that electricians work with what engineers have designed. Let's stop forcing the trade to serve as low paid engineers, huh?
efficiency is attained from motor specs (usually catolog)and power factor is listed on the spec plate, if you look at the code section raider quoted it says you use the tables for blower type motors, multi speed or high torque (pump type direct coupled motors) the type you see more often in large hp you do use FLA. Sometimes you just want a formula to just double check the design engineer, you might be doing an install that is similar to others you have done and see a smaller or larger wire or breaker size and want to check. The motors close to that size I have done are either pump stations, chiller plants or something in that area never done a blower or belt sheave motor over 100 hp.
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Old 04-23-2008, 07:05 AM   #11
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Quote:
Originally Posted by randomkiller View Post
efficiency is attained from motor specs (usually catolog)and power factor is listed on the spec plate, if you look at the code section raider quoted it says you use the tables for blower type motors, multi speed or high torque (pump type direct coupled motors) the type you see more often in large hp you do use FLA. Sometimes you just want a formula to just double check the design engineer, you might be doing an install that is similar to others you have done and see a smaller or larger wire or breaker size and want to check. The motors close to that size I have done are either pump stations, chiller plants or something in that area never done a blower or belt sheave motor over 100 hp.
Wow you're good.
Was that all off the top of your head?
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Old 04-23-2008, 07:09 AM   #12
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Wow you're good.
Was that all off the top of your head?


I do a lot of that type of thing (chiller plants, large boiler plants, pump houses) all the time. I work for an electro mechanical company.
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Old 04-23-2008, 07:17 AM   #13
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Ahh, I see.
Now this is what I meant when I said that experience and not just learning is far greater a source of knowledge.
I'd rather have a guy like you on my team than some newly qualified 3 week course kiddie.
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Old 04-23-2008, 07:21 AM   #14
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Ahh, I see.
Now this is what I meant when I said that experience and not just learning is far greater a source of knowledge.
I'd rather have a guy like you on my team than some newly qualified 3 week course kiddie.

Thanks for the compliment. I agree with the 3 week wonder boy issue. A multi year apprenticeship is what it takes to be a journeymen in my local. It helps if you are with a good contractor from the start.
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Old 04-23-2008, 07:31 AM   #15
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Random killer, I have seen the word "Journeyman on here a lot, what is a journeyman, is it an American term or do we brits use it too?
I must confess I have never heard of it.
The compliment is all yours, it is nice to know that there are still guys who take a pride in what they do and conviction in what they know.
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Old 04-23-2008, 11:30 AM   #16
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Take a look at the book and read that section, keeping in mind it's a 250 hp motor, more than likely a pump motor.
You maybe surprised.
The OPer never stated what type of motor he was installing so I posted the general requirement. You are correct if the motor in question is a multispeed motor, Wye start Delta run motor, Part winding or other than continious duty motor you use the motor nameplate.

Chris
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Old 04-23-2008, 01:00 PM   #17
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You are leaving out efficiency,power factor, and the fact its three phase on the divisor.
I could be wrong; but, if:
  • Efficiency is shaft mechanical-work output divided by electrical-work input, giving a percentage or ratio.
  • Power Factor is electrical-resistive power divided by total electrical-input power. I.e., it gives a percentage or ratio that measures what percent of total power is in-phase, resistive work while excluding inductive, VAR "work".
Is this correct so far?

Then, the difference between efficiency and power factor is that efficiency measures the mechanical output as a percentage of the total EI, while power factor measures electrical output as a percentage of total EI.

In other words, efficiency is affected both by mechanical losses such as bearing friction and by electrical "losses", such as VAR, while power factor is only affected by electrical "losses", such as VAR.

Comments? Corrections?

Thanks,
Mark
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Old 04-23-2008, 02:10 PM   #18
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Thanks for all the input. I currently design systems a lot smaller and have the challenge of a much larger machine. The motor is on a hydraulic pump with a swash plate control valve to prevent huge startup torque. Thanks for nec code insight.
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Old 04-23-2008, 02:16 PM   #19
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Quote:
Originally Posted by raider1 View Post
The OPer never stated what type of motor he was installing so I posted the general requirement. You are correct if the motor in question is a multispeed motor, Wye start Delta run motor, Part winding or other than continious duty motor you use the motor nameplate.

Chris

When was the last time you saw a motor over 75 hp that wasn't a pump, machine, or compressor motor?
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Old 04-23-2008, 02:17 PM   #20
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Quote:
Originally Posted by chollapete View Post
I could be wrong; but, if:
  • Efficiency is shaft mechanical-work output divided by electrical-work input, giving a percentage or ratio.
  • Power Factor is electrical-resistive power divided by total electrical-input power. I.e., it gives a percentage or ratio that measures what percent of total power is in-phase, resistive work while excluding inductive, VAR "work".
Is this correct so far?

Then, the difference between efficiency and power factor is that efficiency measures the mechanical output as a percentage of the total EI, while power factor measures electrical output as a percentage of total EI.

In other words, efficiency is affected both by mechanical losses such as bearing friction and by electrical "losses", such as VAR, while power factor is only affected by electrical "losses", such as VAR.

Comments? Corrections?

Thanks,
Mark

You got it.
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