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Old 01-27-2015, 03:30 AM   #1
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Default Induction motor wound rotor

I have a quick question regarding the wound rotor configuration in an induction motor.

Is it short-circuited during operation? If so why? I kinda know a bit of the answer but just doesn't make any sense for me please give me a good explanation(short and to the point if possible). Thank you!
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Old 01-27-2015, 09:01 AM   #2
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Short answer: it depends...

Applying different amounts of resistance to the rotor circuit changes the magnetics in the rotor, which changes the torque output of the motor. There are two ways of designing a WRIM control system, either for just soft starting or for continuous use under rotor resistance control.

If the design is intended to only be for soft starting and when done, the motor will run at full speed/torque, the resistors and components that change values are often not designed to be in the circuit continuously. If so, you MUST short out the rotor once it is finished accelerating or you will burn them out.

But in other designs, the ability to alter torque is used as an indirect speed control system. If that is the case, the components in the controller will be designed to handle continuous operation, so the only reason to short the rotor is if you want full torque and thus full speed out of the motor. You will not get that if there is any external resistance in the circuit.
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